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z=y^2+2f(1/x+logy) #byeliminatingthearbitraryfunction #PartialDifferentialEquations L1k,221

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Maths Pulse - Chinnaiah Kalpana

11 days ago

z=y^2+2f(1/x+logy) #byeliminatingthearbitraryfunction #PartialDifferentialEquations L1k,221

z=y^2+2f(1/x+logy) #byeliminatingthearbitraryfunction #PartialDifferentialEquations L1k,221

z=y^2+2f(1\/x+logy) #byeliminatingthearbitraryfunction #PartialDifferentialEquations L1k,221
10:09
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