[y(1+1/x)+Cosy]dx+(x+logx-xSiny)dy=0 #ExactEquation #differentialequations

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[y(1+1/x)+Cosy]dx+(x+logx-xSiny)dy=0 #ExactEquation #differentialequations

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Math Study With Pradum

2 months ago

[y(1+1/x)+Cosy]dx+(x+logx-xSiny)dy=0 #ExactEquation #differentialequations

$[y(1+1\/x)+Cosy]dx+(x+logx-xSiny)dy=0 #ExactEquation #differentialequations$

7:50

[y(1+1\/x)+Cosy]dx+(x+logx-xSiny)dy=0 #ExactEquation #differentialequations

by Math Study With Pradum

$[y(1+1\/x)+Cosy]dx+(x+logx-xSiny)dy=0 #ExactEquation L519 @MathsPulseChinnaiahKalpana$

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[y(1+1\/x)+Cosy]dx+(x+logx-xSiny)dy=0 #ExactEquation L519 @MathsPulseChinnaiahKalpana

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Calculus Help: Exact Differential Equations: (siny+ysinx+1\/x)dx+(xcosy-cosx+1\/y)dy=0 - SOLVED!!

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Double Integral of 1\/[(x+y)sqrt{(1-x)(1-y)}] over x, y from 0 to 1

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Q162 Solve {y(1+1\/x) + cosy }dx + {x +logx - xsiny}dy =0

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$If x = √a^sin^-1 t , y = √a^cos^-1 t , show that dy\/dx = -y\/x$

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If x = √a^sin^-1 t , y = √a^cos^-1 t , show that dy\/dx = -y\/x

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$Calculus Help: Separable Differential Equations - cosy+(1+e^(-x) ) siny dy\/dx=0 ,y=π\/4,x=0$

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Calculus Help: Separable Differential Equations - cosy+(1+e^(-x) ) siny dy\/dx=0 ,y=π\/4,x=0

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Calculus Help: Separable Differential Equations - dy\/dx= (x^2+1)\/(2-y) - Technqiues

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$Calculus Help: Exact - Differential Equations - (1\/x+2xy^2 ) dx+(2x^2 y-cosy) dy=0$

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Calculus Help: Exact - Differential Equations - (1\/x+2xy^2 ) dx+(2x^2 y-cosy) dy=0

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[y(1+1/x)+Cosy]dx+(x+logx-xSiny)dy=0 #ExactEquation #differentialequations