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PROVE THAT (SinA+CosecA)^2+(CosA+SecA)^2=7+Tan^A+Cot^2A|PREVIOUS YEAR QUESTIONS PART3|CLASS10 |CBSE|

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PROVE THAT (SinA+CosecA)^2+(CosA+SecA)^2=7+Tan^A+Cot^2A|PREVIOUS YEAR QUESTIONS PART3|CLASS10 |CBSE|

PROVE THAT (SinA+CosecA)^2+(CosA+SecA)^2=7+Tan^A+Cot^2A|PREVIOUS YEAR QUESTIONS PART3|CLASS10 |CBSE|

Prove that (sinA + cosecA)² + (cosA+secA)² = 7 + tan²A + cot²A
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Prove that (sinA + cosecA)² + (cosA+secA)² = 7 + tan²A + cot²A
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Trigonometry Class 10 Ex :- 8.4 Question no. 5 (viii) (SinA+CosecA)² + (CosA+SecA)² = 7+Tan²A+Cot²A
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prove that (sinA + cosecA)² + (cosA + secA)² = 7 + tan²A + cot²A
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Ex8.4-Q5-5. (sinA+cosecA)2+(cosA+secA)2=7+tan2A+cot2A \& (cosecA–sinA)(secA–cosA)=1\/tan A + cot A
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Ex8.4-Q5-5. (sinA+cosecA)2+(cosA+secA)2=7+tan2A+cot2A \& (cosecA–sinA)(secA–cosA)=1\/tan A + cot A
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`(sinA+cosecA)^2+(cosA+secA)^2=7+tan^2A+cot^2A`
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