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J3/2(x) = (√2/√πx)(sin x/x - cos x)|| Recurrence Relation || Bessel's Functions #specialfunctions

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Gari-Math

6 days ago

J3/2(x) = (√2/√πx)(sin x/x - cos x)|| Recurrence Relation || Bessel's Functions #specialfunctions

J3/2(x) = (√2/√πx)(sin x/x - cos x)|| Recurrence Relation || Bessel's Functions #specialfunctions

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