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Janusz
办美国文凭加拿大文凭澳洲文凭英国文凭学位证毕业证成绩单
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Wendy Ye
(a - b)² = a² - 2ab + b², But Why? A quickie explanation of how this "formula"..Shashank Web Series
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5 years ago
(a - b)² = a² - 2ab + b², But Why? A quickie explanation of how this "formula"..Shashank Web Series
![Prove that |[1 +a^2 -b^2, 2ab, -2b],[2ab, 1-a^2 +b^2, 2a],[2b, -2a, 1-a^2 -b^2]| = (1 + a^2 + b^2)^3](http://i.ytimg.com/vi/B7UwIYXEcX8/mqdefault.jpg "Prove that |[1 +a^2 -b^2, 2ab, -2b],[2ab, 1-a^2 +b^2, 2a],[2b, -2a, 1-a^2 -b^2]| = (1 + a^2 + b^2)^3")
![`|[1+a^2-b^2,2ab,-2b],[2ab,1-a^2+b^2,2a],[2b,-2a,1-a^2-b^2]|=(1+a^2+b^2)^3`](http://i.ytimg.com/vi/DZTkxC3aH2Q/mqdefault.jpg "`|[1+a^2-b^2,2ab,-2b],[2ab,1-a^2+b^2,2a],[2b,-2a,1-a^2-b^2]|=(1+a^2+b^2)^3`")
![Prove that |[a - b - c, 2a, 2a],[2b, b - c - a, 2b],[2c, 2c, c - a - b]| = (a + b +c)^3](http://i.ytimg.com/vi/F6Kll3fQIB0/mqdefault.jpg "Prove that |[a - b - c, 2a, 2a],[2b, b - c - a, 2b],[2c, 2c, c - a - b]| = (a + b +c)^3")
