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5:00
Rationalize the denominator|| Find ‘a’ and ‘b’ of : (𝟐+√𝟑)/(𝟐−√𝟑)=𝒂+𝒃√𝟑
11:09
CBSE||CHAPTER 9|| Area and Perimeter|| CLASS 7|| EXERCISE 9.1 | Q3-Q4
9:35
CBSE||CHAPTER 9|| Area and Perimeter|| CLASS 7||EXERCISE 9.1|| Q1-Q2|| SOLUTION
14:46
CLASS 7 MATHS | CHAPTER9 || PERIMETER AND AREA || INTRODUCTION || MATHS || CBSE | NEW EDITION BOOK
8:42
CLASS 7 ,CHAPTER 3, HEAT ,QUESTION ANSWER //BACK EXERCISE /NCERT/CBSE
20:56
class 7 science HEAT /Transfer of heat-CONDUCTION,CONVENCTION & RADIATION,
27:13
Class 7 SCIENCE CHAPTER 3 HEAT/ TYPES OF THERMOMETER//HEAT/TEMPERATURE/PART 1//
3:55
CLASS 7//CHAPTER1// INTEGER// MATHS//CBSE//Q7 //EX 1.3
4:38
CLASS 7//CHAPTER 1//INTEGERS//EX 1.3//Q6
8:41
CLASS 7//CHAPTER1// INTEGER// MATHS//CBSE//EXERCISE 1.3//Q5
13:11
CLASS 7//CHAPTER1// INTEGER// MATHS//CBSE//EX 1.3//Q1-Q4
11:47
CLASS 7//CHAPTER1// INTEGER// MATHS//CBSE//ex 1.2
7:41
CLASS 7//CHAPTER1// INTEGERS / MATHS//CBSE////exercise 1.1//All question
22:56
CLASS 7//CHAPTER1// INTEGER// MATHS//CBSE//introduction
40:41
CLASS 10/ CHAPTER 8/TRIGONOMETRY/CBSE/NEW SYLLABUS/one shot/exam time revision
3:33
CLASS 10/EX-8.3/Q-4(x)/CH-8/TRIGONOMETRY/CBSE/NEW SYLLABUS/(1+𝑡𝑎𝑛2𝐴)/(1+𝑐𝑜𝑡2𝐴)=(1−𝑡𝑎𝑛𝐴)/(1−cot𝐴 )^2
2:04
CLASS 10/EX-8.3/Q-4(ix)/CH-8/TRIGONOMETRY/CBSE/NEW SYLLABUS/(cosec A–sin A)(secA–cosA)=1/(𝑡𝑎𝑛𝐴+𝑐𝑜𝑡𝐴)
2:47
CLASS 10/EX-8.3/Q-4(viii)/CH-8/TRIGONOMETRY/CBSE/NEW SYLLABUS/sinA+cosecA2+cosA+sec A2=7+tan2A+cot2A
2:21
CLASS 10/EX-8.3/Q-4(vii)/ CH-8/TRIGONOMETRY/CBSE/NEW SYLLABUS/ (𝑠𝑖𝑛𝜃−2𝑠𝑖𝑛3𝜃)/(2𝑐𝑜𝑠3𝜃−𝑐𝑜𝑠𝜃)=tanθ
1:46
CLASS 10/EX-8.3/Q-4(vi) / CHAPTER 8/TRIGONOMETRY/CBSE/NEW SYLLABUS/√((1+𝑠𝑖𝑛𝐴)/(1−𝑠𝑖𝑛𝐴))=𝑠𝑒𝑐𝐴+𝑡𝑎𝑛𝐴
4:28
CLASS 10/EX 8.3/Q-4(v)/CH -8/TRIGONOMETRY/CBSE/NEW SYLLABUS/(𝑐𝑜𝑠𝐴−𝑠𝑖𝑛𝐴+1)/(𝑐𝑜𝑠𝐴+𝑠𝑖𝑛𝐴−1)=cosecA+cotA
2:37
CLASS 10/EXERCISE 8.3/Q-4(iv)/ CH-8/TRIGONOMETRY/CBSE/NEW SYLLABUS/(iv) (1+𝑠𝑒𝑐𝐴)/𝑠𝑒𝑐𝐴=𝑠𝑖𝑛2𝐴/(1−𝑐𝑜𝑠𝐴)
8:14
CLASS 10/EX-8.3/Q- 4(ii)/CH-8/TRIGONOMETRY/NEW SYLLABUS/𝑡𝑎𝑛𝜃/(1−cot𝜃 )+𝑐𝑜𝑡𝜃/(1−𝑡𝑎𝑛𝜃)=1+𝑠𝑒𝑐𝜃cosec𝜃
2:18
CLASS 10/EXERCISE 8.3/Q- 4(ii)/ CHAPTER 8/TRIGONOMETRY/CBSE/NEW SYLLABUS
4:52
CLASS 10/EXERCISE 8.3/Q-4(i)/CHAPTER 8/TRIGONOMETRY/CBSE/NEW SYLLABUS
5:45
CLASS 10/EXERCISE 8.3/Q-3 / CHAPTER 8/TRIGONOMETRY/CBSE/NEW SYLLABUS
3:49
CLASS 10/EXERCISE 8.3/Q- 2/ CHAPTER 8/TRIGONOMETRY/CBSE/NEW SYLLABUS
3:32
CLASS 10/EXERCISE 8.3/Q-1 /CHAPTER 8/TRIGONOMETRY/CBSE/NEW SYLLABUS.Express the trigonometric ratios
4:14
CLASS 10/EXERCISE 8.2/Q-4/ CHAPTER 8/TRIGONOMETRY/CBSE/NEW SYLLABUS
3:19
CLASS 10/EX-8.2/Q-3/CH-8/TRIGONOMETRY/CBSE/NEW SYLLABUS/If tan(A+B)=√3 𝑎𝑛𝑑 tan(A−B)=1/√3 find A&B
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